{"id":37284,"date":"2026-04-21T15:10:36","date_gmt":"2026-04-21T07:10:36","guid":{"rendered":"https:\/\/blog-admin.thethinkacademy.com\/?p=37284"},"modified":"2026-06-25T21:24:57","modified_gmt":"2026-06-25T13:24:57","slug":"amc8-counting-and-probability","status":"publish","type":"post","link":"https:\/\/blog-admin.thethinkacademy.com\/blog\/2026\/04\/21\/amc8-counting-and-probability\/","title":{"rendered":"Mastering Counting and Probability for AMC 8: Key Rules and Real Problems"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">Introduction<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><a href=\"https:\/\/www.thinkacademy.ca\/blog\/blog\/2026\/04\/15\/amc-8-math-competition-guide-for-parents\/\">AMC 8<\/a> Counting and Probability is a major topic in the contest and often challenges students who are not yet confident with formulas. These questions include everything from basic counting principles to advanced probability word problems and permutations and combinations. In this guide, we explain the essential rules, show how they work, and highlight AMC 8 past problems that demonstrate each formula. Practicing with worksheets and real contest examples will help students strengthen their problem-solving skills.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This article focuses on <strong>AMC 8 Counting and Probability<\/strong>. For a full study plan, also check out our guides on <a href=\"https:\/\/blog-admin.thethinkacademy.com\/algebra-formulas-for-amc-8\/\">AMC 8 Algebra Formulas<\/a> and <a href=\"https:\/\/blog-admin.thethinkacademy.com\/amc8-geometry-formula-guide\/\">AMC 8 Geometry Formula<\/a>. For a complete overview of the AMC 8 competition including format, scoring, and registration for Canadian students, see our <a href=\"https:\/\/blog-admin.thethinkacademy.com\/blog\/2026\/04\/15\/amc-8-math-competition-guide-for-parents\/\" target=\"_blank\" rel=\"noreferrer noopener\">AMC 8 Math Competition: The Complete Guide for Canadian Students<\/a>!<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><a href=\"https:\/\/www.thinkacademy.ca\/amc-assessment?source_id=6718&amp;source_type=9&amp;utm_medium=website&amp;utm_source=pc_blog\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"562\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-1024x562.png\" alt=\"\" class=\"wp-image-64013\" style=\"aspect-ratio:1.8221334087854566;width:673px;height:auto\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-1024x562.png 1024w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-300x165.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-768x422.png 768w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-1536x843.png 1536w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1-1300x714.png 1300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-72-1.png 1692w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n<\/div>\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Rule or formula<\/th><th>When to use it<\/th><th>AMC 8 example year<\/th><\/tr><\/thead><tbody><tr><td>Sum rule<\/td><td>Counting mutually exclusive cases<\/td><td>2015 Problem 4<\/td><\/tr><tr><td>Product rule<\/td><td>Counting independent sequential steps<\/td><td>2019 Problem 14<\/td><\/tr><tr><td>Basic probability<\/td><td>Finding likelihood of a single event<\/td><td>2014 Problem 16<\/td><\/tr><tr><td>Permutations<\/td><td>Ordered arrangements with restrictions<\/td><td>2018 Problem 16<\/td><\/tr><tr><td>Combinations<\/td><td>Unordered selections from a group<\/td><td>2018 Problem 16<\/td><\/tr><tr><td>Complementary counting<\/td><td>Subtracting unwanted outcomes from total<\/td><td>Various<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\">The Sum Rule: When to Add in AMC 8 Counting Problems<\/h2>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"775\" height=\"235\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/2Oa2hH3qN2dY1Lsc.png\" alt=\"AMC 8 Counting and Probability formula for Sum Rule, showing addition principle in counting methods.\" class=\"wp-image-37290\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/2Oa2hH3qN2dY1Lsc.png 775w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/2Oa2hH3qN2dY1Lsc-300x91.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/2Oa2hH3qN2dY1Lsc-768x233.png 768w\" sizes=\"auto, (max-width: 775px) 100vw, 775px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>AMC 8 Example (2015, Problem 4)<\/strong> &#8211; applying the sum rule<\/h3>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"1010\" height=\"194\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/8GxLmANVUQz1k7YX.png\" alt=\"AMC 8 counting problem with 2 boys and 3 girls arranged in a row using Sum Rule principle.\" class=\"wp-image-37287\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/8GxLmANVUQz1k7YX.png 1010w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/8GxLmANVUQz1k7YX-300x58.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/8GxLmANVUQz1k7YX-768x148.png 768w\" sizes=\"auto, (max-width: 1010px) 100vw, 1010px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">The Centerville Middle School chess team has 2 boys and 3 girls. A photographer wants them in a row with a boy at each end and the girls in the middle.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Case 1: Boy A left, Boy B right \u2192 3! = 63! = 63! =6 ways<\/li>\n\n\n\n<li>Case 2: Boy B left, Boy A right \u2192 3! = 63! = 63! = 6 ways<\/li>\n\n\n\n<li>Total = 6 + 6 = 126 + 6 = 126 + 6 = 12<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This is a straightforward AMC 8 counting problem where the Sum Rule is applied by splitting cases and adding the results.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">The Product Rule: When to Multiply in AMC 8 Counting Problems<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">When a process has independent steps, the total number of ways is:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"806\" height=\"259\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/24HHm4dlxydibaJI.png\" alt=\"AMC 8 Counting and Probability formula for Product Rule, illustrating multiplication principle for independent tasks.\" class=\"wp-image-37291\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/24HHm4dlxydibaJI.png 806w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/24HHm4dlxydibaJI-300x96.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/24HHm4dlxydibaJI-768x247.png 768w\" sizes=\"auto, (max-width: 806px) 100vw, 806px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>AMC 8 Example (2019, Problem 14)<\/strong> &#8211; applying the product rule<\/h3>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"834\" height=\"334\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Cz0Ep5CNigvFOHvA.png\" alt=\"AMC 8 probability word problem about redeeming coupons every 10 days while avoiding Sundays.\" class=\"wp-image-37292\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Cz0Ep5CNigvFOHvA.png 834w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Cz0Ep5CNigvFOHvA-300x120.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Cz0Ep5CNigvFOHvA-768x308.png 768w\" sizes=\"auto, (max-width: 834px) 100vw, 834px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Isabella redeems coupons every 10 days. Pete\u2019s shop is closed on Sundays. After circling six redemption days, none lands on Sunday. What day of the week did she start?<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Each step shifts 3 days forward (10\u22613(mod7)10 \\equiv 3 \\pmod{7}10\u22613(mod7))<\/li>\n\n\n\n<li>Sequence cycles: Start \u2192 +3 \u2192 +6 \u2192 +2 \u2192 +5 \u2192 +1<\/li>\n\n\n\n<li>Only <strong>Tuesday<\/strong> avoids Sunday<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This is a classic AMC 8 probability word problem that combines modular arithmetic with the Product Rule.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Probability Properties: Key Rules for AMC 8<\/h2>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"809\" height=\"494\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/jWko1Hb7STLozuLT.png\" alt=\"AMC 8 Counting and Probability formulas showing basic properties of probability between 0 and 1.\" class=\"wp-image-37289\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/jWko1Hb7STLozuLT.png 809w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/jWko1Hb7STLozuLT-300x183.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/jWko1Hb7STLozuLT-768x469.png 768w\" sizes=\"auto, (max-width: 809px) 100vw, 809px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">\u200b<strong>AMC 8 Example (2016, Problem 21)<\/strong> &#8211; using properties of probability<\/h3>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"994\" height=\"340\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Xt5ioOIml3ls9PiN.png\" alt=\"AMC 8 probability problem with 3 red chips and 2 green chips drawn without replacement.\" class=\"wp-image-37294\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Xt5ioOIml3ls9PiN.png 994w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Xt5ioOIml3ls9PiN-300x103.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/Xt5ioOIml3ls9PiN-768x263.png 768w\" sizes=\"auto, (max-width: 994px) 100vw, 994px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">A box has 3 red chips and 2 green chips. Chips are drawn without replacement until either all 3 reds or both greens appear. What is the probability that all reds are drawn?<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Success happens if the 3rd red comes before the 2nd green<\/li>\n\n\n\n<li>Probability = 3\/5<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Students practicing with probability worksheets will often see problems like this, which test their understanding of basic probability rules.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><a href=\"https:\/\/www.thinkacademy.ca\/amc-assessment?source_id=6718&amp;source_type=9&amp;utm_medium=website&amp;utm_source=pc_blog\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"683\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-1024x683.png\" alt=\"\" class=\"wp-image-64010\" style=\"aspect-ratio:1.499301554042256;width:651px;height:auto\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-1024x683.png 1024w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-300x200.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-768x512.png 768w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-1300x867.png 1300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1-800x533.png 800w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-71-1.png 1536w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n<\/div>\n\n\n<h2 class=\"wp-block-heading\">Permutations and Combinations in AMC 8<\/h2>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"795\" height=\"606\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/rLSXYAB8tV6lnwvk.png\" alt=\"AMC 8 Counting and Probability formulas for permutations, combinations, repeated items, and binomial theorem.\" class=\"wp-image-37288\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/rLSXYAB8tV6lnwvk.png 795w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/rLSXYAB8tV6lnwvk-300x229.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/rLSXYAB8tV6lnwvk-768x585.png 768w\" sizes=\"auto, (max-width: 795px) 100vw, 795px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">AMC 8 Example (2018, Problem 16) <\/h3>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"1244\" height=\"120\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/OpQ8X5QYiP4DVbba.png\" alt=\"AMC 8 permutations and combinations problem arranging 9 language books with grouping restrictions.\" class=\"wp-image-37286\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/OpQ8X5QYiP4DVbba.png 1244w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/OpQ8X5QYiP4DVbba-300x29.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/OpQ8X5QYiP4DVbba-1024x99.png 1024w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/OpQ8X5QYiP4DVbba-768x74.png 768w\" sizes=\"auto, (max-width: 1244px) 100vw, 1244px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Professor Chang has 9 books: 2 Arabic, 3 German, 4 Spanish. Arabic must stay together, and Spanish must stay together.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Treat Arabic and Spanish each as a single block \u2192 7 objects<\/li>\n\n\n\n<li>Arrange 7 blocks: 7!7!7!<\/li>\n\n\n\n<li>Internal arrangements: 2!\u00d74!2! \\times 4!2!\u00d74!<\/li>\n\n\n\n<li>Total = 2880<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This is a good example of AMC 8 permutations and combinations problems, where grouping restrictions make the problem more challenging.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Basic Probability Formulas for AMC 8 Contest Problems<\/h2>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"745\" height=\"350\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/YNkT8pnQHbd0BWaJ.png\" alt=\"AMC 8 Counting and Probability formulas for union and intersection of two or three events.\" class=\"wp-image-37285\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/YNkT8pnQHbd0BWaJ.png 745w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/YNkT8pnQHbd0BWaJ-300x141.png 300w\" sizes=\"auto, (max-width: 745px) 100vw, 745px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>AMC 8 Example (2014, Problem 16)<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-image\"><img loading=\"lazy\" decoding=\"async\" width=\"984\" height=\"180\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/SFt6EXuD0quOgHDs.png\" alt=\"AMC 8 probability problem about calculating total basketball games in a season with internal and external matches.\" class=\"wp-image-37293\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/SFt6EXuD0quOgHDs.png 984w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/SFt6EXuD0quOgHDs-300x55.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2025\/09\/SFt6EXuD0quOgHDs-768x140.png 768w\" sizes=\"auto, (max-width: 984px) 100vw, 984px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">The \u201cMiddle School Eight\u201d basketball conference has 8 teams. Each team plays every other twice plus 4 extra non-conference games.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Internal games: (82) \u00d7 2 = 56{8 \\choose 2} \\times 2 = 56 (28\u200b) \u00d7 2 = 56<\/li>\n\n\n\n<li>Non-conference games: 8 \u00d7 4 = 328 \\times 4 = 328 \u00d7 4 = 32<\/li>\n\n\n\n<li>Total = 88<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This type of AMC 8 probability problem is solved by applying union\/intersection-style counting formulas.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Why counting and probability matters on the AMC 8<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Counting and probability questions appear on every AMC 8 paper without exception. In recent years they have made up between four and six of the 25 questions, which means they represent roughly 20% of a student&#8217;s total score. Students who are confident with the sum rule, product rule, and basic probability formulas going into the contest have a meaningful advantage \u2014 these questions are consistently more accessible than geometry or number theory problems for well-prepared students.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The most common mistake students make is treating each question as a completely new problem rather than recognising which rule or formula applies. The examples in this guide each demonstrate a specific technique. Practising with AMC 8 past contest problems \u2014 particularly from 2014 to 2025 \u2014 and being able to identify the technique before working through the solution is the most effective preparation approach.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For a full overview of all AMC 8 topics and how to structure your child&#8217;s preparation, see our complete AMC 8 guide: <a href=\"https:\/\/blog-admin.thethinkacademy.com\/blog\/2026\/04\/15\/amc-8-math-competition-guide-for-parents\/\">AMC 8 Math Competition: The Complete Guide for Canadian Students<\/a>.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large is-resized\"><a href=\"https:\/\/www.thinkacademy.ca\/amc-free-trial?source_id=6718&amp;source_type=9&amp;utm_medium=website&amp;utm_source=pc_blog\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"512\" src=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-1024x512.png\" alt=\"\" class=\"wp-image-64016\" style=\"aspect-ratio:2.0000388213828177;width:685px;height:auto\" srcset=\"https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-1024x512.png 1024w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-300x150.png 300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-768x384.png 768w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-1536x768.png 1536w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74-1300x650.png 1300w, https:\/\/blog-admin.thethinkacademy.com\/wp-content\/uploads\/2026\/04\/Untitled-design-74.png 1774w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Introduction AMC 8 Counting and Probability is a major topic in the contest and often challenges &hellip; <a title=\"Mastering Counting and Probability for AMC 8: Key Rules and Real Problems\" class=\"hm-read-more\" href=\"https:\/\/blog-admin.thethinkacademy.com\/blog\/2026\/04\/21\/amc8-counting-and-probability\/\"><span class=\"screen-reader-text\">Mastering Counting and Probability for AMC 8: Key Rules and Real Problems<\/span>Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":61128,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[17153,1752],"tags":[12168,12170,12174,12175,12173,12176,12169,12172,12171,12177],"class_list":["post-37284","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-amc-category","category-competitions","tag-amc-8-counting-and-probability","tag-amc-8-counting-problems","tag-amc-8-formulas","tag-amc-8-past-problems","tag-amc-8-permutations-and-combinations","tag-amc-8-practice-worksheets","tag-amc-8-probability-problems","tag-amc-8-probability-worksheets","tag-amc-8-word-problems","tag-math-contest-probability-problems"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.5 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>AMC 8 Counting and Probability Formulas | Think Academy CA<\/title>\n<meta name=\"description\" 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